Question

Q.27 If secA = 12/5 find sin²A + tanA.​

Answer 1

Given:

secA = 12/5

To find:

sin²A + tanA

Solution:

We have given the value of the trigonometric term of Sec A as:

secA = 12/5

and as per the formula of the ratio of the trigonometric term we get:

secA = H/B

To find the value of the P use the Pythagoras theorem

• H² = P²+B²
• 12² = P² + 5²
• P² = 144 - 25
• P² = 119
• P = √119

sin²A + tanA

• (P/H)² + P/B
• (√119/12)² + √119/5
• 119/114 + √119/5

Hence,

The value of sin²A + tanA is 119/114 + √119/5