Q.27 If secA = 12/5 find sin²A + tanA.
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Given:
secA = 12/5
To find:
sin²A + tanA
Solution:
We have given the value of the trigonometric term of Sec A as:
secA = 12/5
and as per the formula of the ratio of the trigonometric term we get:
secA = H/B
To find the value of the P use the Pythagoras theorem
- H² = P²+B²
- 12² = P² + 5²
- P² = 144 - 25
- P² = 119
- P = √119
sin²A + tanA
- (P/H)² + P/B
- (√119/12)² + √119/5
- 119/114 + √119/5
Hence,
The value of sin²A + tanA is 119/114 + √119/5
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