Question

Q.27. In a right angled AABC, AC is the hypotenuse and the other two sides are of length 12 m
and 9 m. X is a point outside the triangle such that XA = 36 m and ZXAC = 90°. Find XC ​

Answer 1

Answer:

12²+9²=AC²

144+81=AC²

AC=√225

AC=15

similarly

36²+15²=XC²

XC =√1521

XC =39

Answer 2

Answer:

answer ........hai bhai ..................,...