Question

Q.27. (n + 1)! -- n! can be expressed as
(a) (n)!
(c) nx(n)!
(b) (n + 1)x(n)!
(d) (n + 1)​

Answer 1

Answer:

Answer:–

• n×(n!)

Given:–

The expression is,

(n+1)!-n!

As we know that,

(n+1)!=(n+1)(n!)

By using this,

Substitute the above value in the given expression,

→ (n+1)!-n!

→ (n+1)(n!)-n!

→ n!(n+1-1)

→ n!(n)

So,

(n+1)!-n!=n!×(n)