Question

Q.27 Prove that:
this equation is equal to 0​

Answer 1

Answer:

1

Step-by-step explanation:

$(\frac{ x^{a} }{ x^b})^{ a+b} (\frac{ x^{b} }{ x^c})^{ b+c}(\frac{ x^{c} }{ x^a})^{ c+a}\\\\=x^ {(a-b)(a+b)} \times x^ {(b-c)(b+c)} \times x^ {(c-a)(c+a)}\\\\=x^ {(a^2-b^2)} \times x^ {(b^2-c^2)} \times x^ {(c^2-a^2)} \\\\=x^ { (a^2-b^2+b^2-c^2+c^2-a^2)}\\\\=x^0\\=1$