Question

Q 27- The sum of first three terms of an A.P is 54 & the tenth term is 58. Then the 1st term of the A.P is​

Answer 1

Answer:

Given, sum of the 5th and 7th term is 52.∴a+4d+a+6d=52⇒2a+10d=52⟶(1)And, the 10th term is 46.∴a+9d=46multiplying it by 2 we get,2a+18d=92⟶(2)Solving equations (1) and (2) we get,8d=40⇒d=5Substituting the value of d in (1) we get,2a+(10×5)=52⇒2a=52−50⇒a=1Therefore, the required A.P. is,1,6,11,16,21,26,31,

Step-by-step explanation:

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