Question

Q 28 is my question
Please ignore the quality of the picture.

Answer 1

$\sqrt{\frac{1+sin\theta}{1-sin\theta}} +\sqrt{\frac{1-sin\theta}{1+sin\theta}}\\ \mathrm{Cross \: multiply \: to \: get} \\ \frac{1+\mathrm{sin}\theta +1-\mathrm{sin}\theta }{\sqrt{1-\mathrm{sin}^2\theta}}\\ =\frac{2}{\sqrt{\mathrm{cos}^2\theta}}\\ = \frac{2}{\mathrm{cos}\theta}\\ =\boxed{\textcolor {red}{\mathrm{2sec}\theta}} \: \mathrm{since} \\ \frac{1}{\mathrm{cos}\theta}=\mathrm{sec}\theta \\ \huge \mathcal{\textcolor{cyan}{Hope \: this \:helps}}$