Question

Q 28 Prove that the ratio of the areas of similar triangles is equal to the ratio of the squares on the
corresponding sides
Using the above result, find the ratio of the areas of AADC and AABC when ABC is right-angled triangle
at A with AD I BC, BC = 12 cm and AC = 5 cm.​

Answer 1

Answer:

Step-by-step explanation:

Also area of abc and adc

We have

Ar adc /ar abc =12 ×12/5×5=144/25

For proving it similar we have d and a=90 and c is common

Hence they r congrant by AA