Question

Q 28) Solve: (x - 6) (x + 7) = (x + 3) (x – 1​)

Answer 1

Answer

(x+6/x+7)-(x+1/x+2) = 1/(3x+1)

[(x+6)(x+2)]-[(x+1)(x+7)]/(x+7)(x+2)=1/(3x+1)

[x^2+2x+6x+12]-[x^2+7x+x+7]/(x+7)(x+2)=1/(3x+1)

(x^2+8x+12)-(x^2+8x+7]/(x+7)(x+2)=1/(3x+1),here x^2-x^2=0,8x-8x=0

[x^2+8x+12-x^2–8x-7]/(x+7)(x+2)=1/(3x+1)

12–7/(x+7)(x+2)=1/(3x+1)

5/[x^2+2x+7x+14]=1/(3x+1)

5(3x+1)=x^2+2x+7x+14

15x+5=x^2+9x+14

x^2+9x-15x+14–5=0

x^2–6x+9=0

x^2–3x-3x+9=0

x(x-3)-3(x-3)=0

(x-3) or (x-3)

x-3=0

x=3

Step-by-step explanation:

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Answer 2

Answer:

(x - 6) (x + 7) = (x + 3) (x – 1)

so the value of x is -39