Question

Q 29. The sides of a triangle are 8 cm,
11 cm and 13 cm. What is its area(in
cm square)? (ਇੱਕ ਤਿਭੁਜ ਦੀ ਭੁਜਾਵਾਂ 8 ਸਮ, 11
12 m, for​

Answer 1

Answer:

8√30 cm²

Explanation:

In a triangle, three sides are 8cm, 11cm, and 13cm

Calculate the area of the traingle.

Area of the triangle is given by,

Heron's formula :

$\bf \longrightarrow \: \sqrt{s(s - a)(s - b)(s - c)}$

Where,

• s denotes the semi-perimeter

And,

• a, b, and c denotes the three side respectively.

Calculating ‘s’ :-

$\sf \longrightarrow \: semi-perimeter = \dfrac{a + b + c}{2}$

$\sf \longrightarrow \: s = \dfrac{8 + 11 + 13}{2}$

$\sf \longrightarrow \: s = \dfrac{32}{2}$

$\sf \longrightarrow \: s= 16$

Now, substitute the values in heron's formula :+

$\sf\longrightarrow \: \sqrt{16(16 - 8)(16 - 11)(16 - 13)}$

$\sf\longrightarrow \: \sqrt{16(8)(5)(3)}$

$\sf\longrightarrow \: \sqrt{ \underline{2 \times 2} \times \underline{2 \times 2} \times \underline{2 \times 2} \times 2 \times 5 \times 3}$

$\sf\longrightarrow \: 8\sqrt{30}$

${ \underline{ \sf{ \therefore{area \: of \: the \: triangle \: is \: 8 \sqrt{30} {cm}^{2} }}}}$

Answer 2

Answer:

refer to the above attachment