Question

Q 2º A boy walks a distana 30 m the 1 minute and
another 30 m in 1. 5 minute. Describe the
of motion of the boy and find his average

speed
in m s-1.
​

Answer 1

Answer:

Total distance travelled in going and coming back

D = 30m + 30m = 60 m

Total time taken in going and coming back

t= 1 min + 1.5 min =2.5 min

= 2.5 60 s

= 150 s

Average speed = \frac{totaldis\tan ce\ \ travelled}{total\ time\ of\ travel}=\ \frac{60m}{150s}

=0.4 m\ s^{-1}

Answer 2

Answer:

Step-by-step explanation:

The boy covers 30m in the first 1 min and again 30m in 1.5min.

First we calculate t1= 30 m/min

t2= 30/1.5 m/min= 20 m/min

As the speed of the boy doesn't remain constant his motion is nonuniform.

Average Speed

Distance=30m

Time=1.5 min=90s

Average v= 30/90 m/s=0.3m/s