Q.3: A bicycle increases its velocity from 18 Km/h to 54 Km/h in 10 seconds.Calculate its acceleration on.
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Answered by
15
Answer:-
Given:
Initial Velocity of the bicycle (u) = 18 km/h
→ u = 18(5/18) = 5 m/s
Final Velocity of the bicycle (v) = 54 km/h
→ v = 54(5/18) = 15 m/s
Time (t) = 10 s.
We know that,
Acceleration (a) = (v - u)/t
→ a = (15 - 5)/10
→ a = 10/10
→ a = 1 m/s²
Hence, the acceleration of the bicycle is 1 m/s².
Answered by
31
Given:-
- Initial velocity (u) = 18 km/h
- Final velocity (v) = 54 km/h
- Time taken (t) = 10 seconds
To Find: Acceleration (a) in this case.
We know,
a = (v - u)/t
where,
- a = Acceleration,
- v, u = Final and initial velocities respectively,
- t = Time taken.
∴ a = [(54 - 18) km/h]/10 s
→ a = (36 km/h)/10 s
→ a = (10 m/s)/10 s
→ a = 1 m/s²
➯ Acceleration in this case was (1 m/s²).
Note: To the change the magnitude of velocity from (km/h) to (m/s), multiply the value with (5/18).
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