Question

Q.3: A bicycle increases its velocity from 18 Km/h to 54 Km/h in 10 seconds.Calculate its acceleration on.

Answer 1

Answer:-

Given:

Initial Velocity of the bicycle (u) = 18 km/h

→ u = 18(5/18) = 5 m/s

Final Velocity of the bicycle (v) = 54 km/h

→ v = 54(5/18) = 15 m/s

Time (t) = 10 s.

We know that,

Acceleration (a) = (v - u)/t

→ a = (15 - 5)/10

→ a = 10/10

→ a = 1 m/s²

Hence, the acceleration of the bicycle is 1 m/s².

Answer 2

Given:-

• Initial velocity (u) = 18 km/h
• Final velocity (v) = 54 km/h
• Time taken (t) = 10 seconds

To Find: Acceleration (a) in this case.

We know,

a = (v - u)/t

where,

• a = Acceleration,
• v, u = Final and initial velocities respectively,
• t = Time taken.

∴ a = [(54 - 18) km/h]/10 s

→ a = (36 km/h)/10 s

→ a = (10 m/s)/10 s

→ a = 1 m/s²

➯ Acceleration in this case was (1 m/s²).

Note: To the change the magnitude of velocity from (km/h) to (m/s), multiply the value with (5/18).