Question

Q.3) A body starts from rest and moves with uniform acceleration of 4m/s2 .How much time will it take to cover a distance of 128m?
Given : u=0 , a = 4m/s2 , s = 128m
To find : t = ?

Answer 1

Initial velocity = 0 m/2

Acceleration = 4 m/s^2

distance = 128 cm = 0.128 m

using the equation d = Vi * t + (1/2) *a*t^2

since Vi = 0 , the term Vi * t = 0

therefore:

d = (1/2)at^2

rearranged for time:

square root of (2d)/a = square root of [(0.256m)/(4m/s^2)]

= sqrt 0.64

= 0.8 seconds

Answer 2

Answer:

heyya

here is your answer

initial velocity= 0 m/ 2

acceleration =4m/s²

distance =128cm=0.128m

using the equation, d=vi*t+(1/2)*a*t²

since, vi=0, the term vi*t=0

therefore:

d=(1/2)at^2

rearranged for time:

square root of (2d)/a= square root of ,

[(0.256m)/(4m/s²)]

=_/0.64

=0.8 seconds

hope this helps you

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