Question

Q.3) ABCD is a trapezium in
which AB II CD and Angle A=
45°. The measure of Angle D
will be ?
​

Answer 1

$\huge{\orange{\underbrace{\bf{AnSweR:}}}}$

Given,

$\sf {ABCD\; is\;a\; Trapezium}$

$\sf {AB\; || \;CD \;and \;Angle \;A = 45°}$

We know that

$\boxed {\bf{Adjacent\; Angles\;of\;a\; Trapezium\;are\; Supplementary (180°)}}$

So,

$➝ Angle\;A + Angle\;D = 180°$

$➝ 45°+Angle\;D = 180°$

$➝ Angle\;D = 180°-45°$

$➝ Angle\;D = 135°$

$\underline{\bf{✯Required\; Answer}}$

Measure of Angle D ☞ $\fbox\red {135°}$

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