Question

Q. 3 axb' is equal to
A (ab)
o
B. (ab)"
C. (a*b)3
D. (a/b)​

Answer 1

Answer:

We know that,

A×B=ABsinθ

Also, A.B=ABcosθ

Given : ∣A×B∣=

3

A.B

Using ∣A×B∣=∣A∣∣B∣sinθ

We get ∣A×B∣=ABsinθ

A.B=∣A∣∣B∣cosθ

∴ ABsinθ=

3

ABcosθ

tanθ=

3

⟹θ=60

o

Now (A+B)

2

=A

2

+B

2

+2A.B

=A

2

+B

2

+2ABcosθ

=A

2

+B

2

+2AB×

2

1

=A

2

+B

2

+AB

or ∣A+B∣=(A

2

+B

2

+AB)

1/2

Answer 2

Answer:

C. (a*b)3

Step-by-step explanation:

this is correct answer