Q. 3. B) Solve the following questions. [Any two]
i) Prove that :v sec?0 + cosecao = tan 0 + cot 0
Solution: Method I
LHS = Sec’e + Coseco
= V1 + tan’0 + 1 + cot? 0
.... [1+tan?o=sec?0, 1+cot²0 = cosec20]
= tan’O + 2 + coto
=
tan @ + 2 tan 0 cot 0 + cot²0
=
V(tan 0 + cot e )
....[a2+2ab+bº=(a+b)2]
=
tano + coto
....(Taking positive square root]
- LHS = RHS
.
Secʻ0 + Cosec?0 = tano + cote
how is this answer possible?
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no this seems to wrong method used
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