Physics, asked by alinaqureshi239, 1 month ago

Q.3 Class Test 2 Work Power & Energy PHYSICS NMDCAT How much work must be done by a force on a 50 kg body in order to accelerate it from rest to 20 m/s in 10 sec. A) 2x 103 C) 103j B) 10 4 j D) 4x10 j STAR INSTITUTE LAHORE​

Answers

Answered by ShivamKashyap08
45

Answer:

  • The work done by the force is 10⁴ J

Explanation:

Given, Mass (M) = 50 Kg

          Initial velocity (u) = 0 m/s

          Final velocity (v) = 20 m/s

          Time taken (t) = 10 sec

From work energy theorem we know that,

\longrightarrow\sf W=\dfrac{1}{2}\;.\;m\bigg(v^{2}-u^{2}\bigg)

Substituting the values,

\\\\\\\\\longrightarrow\sf W=\dfrac{1}{2}\times 50 \times \bigg((20)^{2}-(0)^{2}\bigg) \\\\\\\\\longrightarrow\sf W=\dfrac{1}{2}\times 50 \times 400 \\\\\\\\\longrightarrow\sf W=50 \times 200\\\\\\\\\longrightarrow\sf W= 10000\\\\\\\\\longrightarrow\sf W=10^{4}\;J

∴ The work done by the force is 10⁴ J.

Answered by StudyKing001
89

Given :-

  • Mass of the body is 50 kg.
  • Initial Velocity = 0 (as it starts from rest)
  • Final Velocity = 20 m/s
  • Time = 10s

To Find :-

  • Work Done = ?

Solution :-

{\red{✧}}{\underline{\bf{ We \:  know \:  that :}}}

{\large{\red{\bigstar \:  \: {\blue{\underbrace{\underline{\orange{\bf{W = \frac{1}{2}   \times M(V² - U²)}}}}}}}}}

{\red{✧}}{\underline{\bf{ Work\:  done:}}}

{\large{:{\longmapsto{\bf{W = \frac{1}{2}  \times m( {v}^{2} -  {u}^{2} )  }}}}}

{\large{:{\longmapsto{\bf{ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \frac{1}{2}  \times 50( {20}^{2} -  {0}^{2} )  }}}}}

{\large{:{\longmapsto{\bf{  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \frac{1}{2}  \times 50( 400 -  {0})  }}}}}

{\large{:{\longmapsto{\bf{  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \frac{1}{2}  \times 50 \times 400  }}}}}

{\large{:{\longmapsto{\bf{  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \frac{1}{\cancel{2}}  \times {\cancel{20000 }}}}}}}

{\large{:{\longmapsto{\bf{  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: 1 \times 10000}}}}}

{\large{:{\longmapsto{\bf{  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: 10000 \: j}}}}}

{\large{\purple{:{\longmapsto{\underline{\overline{\boxed{\bf{  {10}^{4}  \: J}}}}}}}}}

{\red{✧}}{\underline{\bf{Therefore :}}}

{\large{\red{\underline{\green{\underline{\orange{\mathfrak{Work  \: Done =  {10}^{4} \:  Joules}}}}}}}}

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