Q.3 Class Test 2 Work Power & Energy PHYSICS NMDCAT How much work must be done by a force on a 50 kg body in order to accelerate it from rest to 20 m/s in 10 sec. A) 2x 103 C) 103j B) 10 4 j D) 4x10 j STAR INSTITUTE LAHORE
Answers
Answered by
45
Answer:
- The work done by the force is 10⁴ J
Explanation:
Given, Mass (M) = 50 Kg
Initial velocity (u) = 0 m/s
Final velocity (v) = 20 m/s
Time taken (t) = 10 sec
From work energy theorem we know that,
Substituting the values,
∴ The work done by the force is 10⁴ J.
Answered by
89
⇝Given :-
- Mass of the body is 50 kg.
- Initial Velocity = 0 (as it starts from rest)
- Final Velocity = 20 m/s
- Time = 10s
⇝To Find :-
- Work Done = ?
⇝Solution :-
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