Question

Q.3. Convert following:
(i) (1024)10 = (?)2
(ii) (11011.001)2 = ( ? )10
(iii) (9A2C)16 = ( ? )
(IV) ADD 110011+011011=(?)​

Answer 1

Answer:

1) (5120)2= (1024)10

2) (2202.2002)10=(11011.001)2

4) 121022=110011+011011