Question

Q.3. Divide: 9x - 6x² + x^3- 2 by (x - 2)
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Answer 1

Answer:

Q. To divide $9x - 6x^2 + x^3 - 2$ by $(x - 2)$

Let the dividend be p(x), divisor be q(x), quotient be q(x) and remainder r(x)

By Euclid's Division,

p(x) = q(x) × g(x) + r(x)

If we make g(x) make 0,

p(x) = r(x)

This is the basis of remainder theorem.

Let g(x) = 0,

⇒ $x - 2 = 0$

⇒ $x = 2$

Now, placing the value of x in p(x), we get:

p(2) = 9 × 2 - 6 × 2² + 2³ - 2

      = 18 - 24 + 8 - 2

      = 0

∴ Remainder = 0

I hope you understand # please mark it the brainliest

Answer 2

Step-by-step explanation:

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