Q.3. Find cubic polynomial p(x) = x3 + 2x2 – 3x. Also verify the
relationship between the zeros and coefficients of p(x). (3)
Answers
Answer:
Step-by-step explanation:
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Given : p(x) = x³ + 2x² - 3x
To Find : Zeroes and verify relationship between coefficients
Solution:
p(x) = x³ + 2x² - 3x
x³ + 2x² - 3x = 0
=> x(x² + 2x - 3) = 0
=> x(x² + 3x - x - 3) = 0
=> x(x (x + 3) - 1(x + 3) ) = 0
=> x(x - 1) (x + 3) = 0
=> Zeroes are
0 , 1 - 3
P(x) = ax³ + bx² + cx + d
p(x) = x³ + 2x² - 3x
=> a = 1 , b = 2 , c = - 3 , d = 0
Sum of zeroes = - b/a = - 2/1 = - 2
Sum of zeroes = 0 + 1 - 3 = - 2
-2 = - 2 verified
Sum of product of zeroes 2 taken at time = c/a = -3/1 = - 3
0(1) + 0(-3) + 1(-3) = -3
-3 = - 3 verified
product of zeroes 3 taken at time = -d/a = -0/1 = 0
0(1)(-3) = 0
0 = 0 verified
Zeroes are 0 ,1 - 3
relationship between the zeros and coefficients of p(x) verified
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