Q.3 Find two solutions for the equation 4x - 3y = 42.
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Given equation is 4x+3y =12
case 1. When X = 0 we get
3y = 12
therefore y = 4
then (0,4) is the first solution.
and case.2 When Y =0
we get 4x = 12
therefore x = 3
therefore (0, 3) is the second solution
Hence (0,4) and (0, 3) are the two solution.
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