Math, asked by mayankpatil0206, 9 months ago

Q.3. For p(x) = x²-7√7x+ 3 find p(7√7)​

Answers

Answered by padigarbhavani
3

Answer:

Hey mate! Here's your answer:

Step-by-step explanation:

p(x) = x² - 7√7x + 3

If x = 7√7,

p(7√7) = (7√7)² - 7√7(7√7) + 3

p(7√7) = 343 - 343 + 3

p(77) = 3.

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Answered by Anonymous
2

Answer :

we have,

p (x) = x^{2} - \sqrt[7]{7x} + 3

put x = \sqrt[7]{7}

therefore,

p (\sqrt[7]{7} ) = \sqrt[7]{7}x^{2} - \sqrt[7]{7} (\sqrt[7]{7}) + 3

p ( \sqrt[7]{7} ) = 343 - 343 + 3

p ( \sqrt[7]{7} ) = 3

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