Q.3. Given that HCF(2520,6600)=120 , LCM(2520,6600)=252K then the value of K
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LCM(2520,6600) =
(2520 ×6600)/ HCF(2520,6600)
=> 252k = 2520×6600/120
k= 550
(2520 ×6600)/ HCF(2520,6600)
=> 252k = 2520×6600/120
k= 550
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