Q 3. If 3x + k, 2x + 9 and x + 13 be any three consecutive terms of
an AP, find the value of k.
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4
Answer:
k = 5
Explanation :
Refer the attached picture.
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3
Answer:
d = 2x + 9 - (3x + k) = x + 13 - (2x + 9)
9 - k - x = 4 - x
9 - k - x + x = 4
9 - k = 4
9 - 4 = k
5 = k
k = 5
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