Q.3 In an A.P., every term
multiplied by 5 and then subtracted by 2, the new common difference will
Choose answer:
Remain same
Subtracted by 2
Multiplied by 5
Multiplied by 5, then subtracted by 2
Answers
In an AP, every term is multiplied by 5 and then subtracted by 2.
To find : The new common difference
solution : let a is first term and d is the common difference of an AP.
so sequence is ; a , a + d , a + 2d , a + 3d , .......
now every term is multiplied by 5 and then subtracted by 2.
new sequnce is ; 5a - 2, 5(a + d) - 2, 5(a + 2d) - 2 , 5(a + 3d) - 2 .....
so the new common difference = difference of two consecutive terms
= 5(a + d) - 2 - (5a - 2)
= 5a + 5d - 2 - 5a + 2
= 5d
Therefore the new common difference is 5 times of its initial common difference.
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