Question

Q.3 In the given circle, O is center of the circle and ZOAB = 30' and ZOCB = 57' Find ZBOC and

ZAOC.​

Answer 1

in figure,

OA=OB=OC

so,∠OCB=∠OBC

also,∠OBA is 30°

so, ∠ABC=27°

similarly, ∠BAC=27°

⇒∠BAC=∠ABC

⇒AC=BC

⇒∠AOC=∠BOC                       ....(1)

now by ASP in ΔBOA,

∠BOA=120°

∴∠BOC=∠AOC=60°                 (using (1) ).