Question

Q.3
In the given figure, ABCD is a trapezium and the lengths of its parallel sides are 10 cm and 17 cm. If the area of ΔABD is 70 cm2, then the area of the trapezium is

Answer 1

Area of trap=

2

1

×(AB+CD)×DE

In right △AED,DE=

AD

2

+AE

2

AE=AB−BE=16−8=

∴DE=

(17)

2

−(8)

2

=

284−64

=

225

=15m

Hence, ar. trap=

2

1

×(8+16)×15=12×15=180m

2

Answer 2

Challange accepted my id 2181046483