Question

Q:3 Rajeev and Reema started walking to the West and the North respectively, from the same point and

at the same speed. After 3 hours distance between them was 27√2 km. Find their speed per hour.​

Answer 1

Given :- Rajeev and Reema started walking to the West and the North respectively, from the same point and at the same speed. After 3 hours distance between them was 27√2 km. Find their speed per hour. ?

Solution :-

Let speed of them is x km/h .

so,

→ Distance travelled by both in 3 hours = 3 * x = 3x km .

then, according to pythagoras theorem,

→ (3x)² + (3x)² = (27√2)²

→ 9x² + 9x² = 729 * 2

→ 18x² = 729 * 2

→ x² = 81

→ x = 9 km/h (Ans.)

Hence, their speed is 9km/h .

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Answer 2

Given :  Rajeev and Reema started walking to the West and the North respectively, from the same point and at the same speed.

After 3 hours distance between them was 27√2 km.

To Find : their speed per hour.​

Solution:

Let say speed per hour  = s km/hr

Distance = Speed * time

Distance covered in 3 hrs  = 3s  km

Rajeev went to west  hence  3s km  West

Reema went to North Hence  3s km North

         NORTH

WEST                   EAST

         SOUTH

North and West are perpendicular to each other

Hence Distance between them = √(3s)² + (3s)²

= 3s√2  km

distance between them was 27√2 km.

Equating both

=>  3s√2 =  27√2

=> s = 9

their speed per hour.​ = 9 km/hr

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