Q.3) Solve the following
2. Two tungsten bulbs of wattage 100 W and 60 W power work on 220 V potential
difference. if they are connected in parallel, how much current will flow in the main
conductor?
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Answer:
potential are same in resistor when they are connected in parallel
so now for 1st bulb
power= 100w
potential= 220v
so as we know power=potential x current
so here current =100/220
which gives u 0.45
now for second bulb
power = 60 w
potential= 220v
so again power=potential x current
current = 60/220
so it will be 0.27
now add 0.45 A and 0.27 A which gives u required ans is 0.72 ampere
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