Question

Q - 3 Solve the sums. 5. The area of rhombus is 120 cm2 and one of the diagonals is 8 cm. Find the other diagonal.

6. The diagonal of a quadrilateral shaped field is 24 m and the remaining opposite verticals

are 8 m and 13 m . Find the area of the field ​

Answer 1

Answer:

5) area of rhombus = ½×product of both diagonals

area = 120cm²

one diagonal = 8cm

let the other diagonal be = x

therefore, ½×x×8 = 120

=> 4x = 120

=> x = 30cm

therefore, the other diagonal is 30cm

6) we can imagine the quadrilateral as two triangles with each of its base = diagonal = 24m

area of 1st ∆ = ½BH

B = 24cm

H = 8cm

therefore, area = ½×24×8

= 96cm²

area of 2nd ∆ = ½BH

B = 24cm

H = 13cm

therefore, area = ½×24×13

= 156cm²

therefore, total area of the quadrilateral =

96+156

= 252cm²

hope it helped :)