Question

Q 3. The displacement x of a particle at time t is
given by x = ao - a1t + a2tsquare. The acceleration of the
particle is:
[a] ao
[b]a1
[C] 2a2
[d] a2​

Answer 1

Given :-

Position of Particle = x = ${a}_{0}-{a}_{1}t+{a}_{2}{t}^{2}$

We are required to find the acceleration of Particle.

Here, we will double differentiate 'x' w.r.t 't'.

V = dx/dt

V = d(a0 - a1t + a2t²)/dt

V = -a1 + 2a2t

Again, Differentiating 'V' w.r.t 't'

a = dV/dt

a = d(-a1 + 2a2t)/dt

$a\:= 2{a}_{2}$

Hence,

Option (C) is correct.