Math, asked by tanuj6844, 2 months ago

Q.3
The factors of 121 p2 - 49 q2 are

Answers

Answered by poojithashankar2008

1

121 p² - 49 q²

rewrite 121p² - 49p² as ( 11 p ) ² - ( 7p ) ² . the difference of squares can be factored using the rule : a² - b² = ( a - b ) ( a + b )

( 11p - 7q ) ( 11p + 7q )

hope helpful for you

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