Question

Q.3. The quadratic polynomial, the sum of whose zeroes is -5 and their product is 6, is:
a) x square + 5x + 6
b) x square - 5x + 6
c) x square - 5x - 6
d) - x square + 5x + 6
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Answer 1

Answer:

f(x) = 6x2 – 3 – 7x

We put f(x) = 0

⇒ 6x2 – 3 – 7x = 0

⇒ 6x2 – 9x + 2x – 3 = 0

⇒ 3x(2x – 3) + 1(2x – 3) = 0

⇒ (2x – 3)(3x + 1) = 0

This gives us 2 zeros, for

x = 32 and x = −13

Hence, the zeros of the quadratic equation are 32 and −13.

Now, for verification Sum of zeros = –coefficientofxcoefficientofx2

32 + (−13) = – (−7)6

76 = 76

Product of roots = constantcoefficientofx2

32 x (−13) = (−3)6

−12 = −12

Therefore, the relationship between zeros and their coefficients is verified.

Answer 2

Answer:

yup the upper answer is correct