Q.3. The sum the ages of two brothers is 25 years and their difference is 3 years. Find their ages.
1 point
14 years ,11 years
13 years,12 years
20 years ,5 years
none of these
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Answer:
3. The sum the ages of two brothers is 25 years and their difference is 3 years. Find their ages.
Step-by-step explanation:
11+14 11×2 = 22 +3= 25 age difference 3 year
14 years ,11 years
hence age of two brothers is 14 y and 11 y
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GIVEN :-
- the sum of the ages of two brother is 25 years
- the difference between the ages of two brother is 3 years.
TO FIND :-
- Ages of both brothers.
SOLUTION :-
▪︎Let the age of first brother is x years
▪︎ Age of second brother is y
sum of age,
⇒ x + y = 25
⇒ x = 25 - y ------------------(1)
Difference of age,
⇒ x - y = 3
⇒ 25 - y - y = 3
⇒ 25 - 2y = 3
⇒ -2y = 3 - 25
⇒ -2y = -22
⇒ y = -22/-2
⇒ y = 11 -------------------(2)
Now put the value of y in Equation 1,
⇒ x = 25 - y
⇒ x = 25 - 11
⇒ x = 14
Hence their ages be 14 years and 11 years.
VERIFICATION :-
❂ Sum of ages = 25
⇒ x + y = 25
⇒ 14 + 11 = 25
⇒ 25 = 25
L.H.S = R.H.S
❂ Difference of ages = 3
⇒ x - y = 3
⇒ 14 - 11 = 3
⇒ 3 = 3
L.H.S = R.H.S