Q 3. Without finding the cubes, factorise (x - y) + (y - z) + (z - x)".
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Answer:
3(x-y)(y-z)(z-x)
Step-by-step explanation:
(x-y)³ + (y-z)³ + (z-x)³
here, a³+b³+c³ = 3abc
because a+b+c = x-y+y-z+z-x
= 0
(x-y)³+(y-z)³+(z-x)³ = 3(x-y)(y-z)(z-x)
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