Question

Q 30/45 From 320 mg of O2, 6.023 x 1021 molecules
are removed, the number of moles remained are
9x 10-3 moles
9x10-2 moles
Zero
3x10-3 moles​

Answer 1

Answer:

32g of O2=1mol=6.023×1023 molecules

∴320mg=0.32g=0.01mol=6.023×1021

From this 6.023×1020 moles are removed= 0.001 moles

∴ Remaining= 0.01−0.001=0.009 moles

=9×10−3 moles .

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Answer 2

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