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Answer:
Q. The sum of the digits of a two digit number is 10 and the digit at units place is 2/3rd of the digit at tens place. Find the number.
Solution:
Let the 10s digit of two digit number be x and 1s digit be y
Hence the number is 10x + y
The number of two digits if a two digit number is 10. It means
x + y = 10…Eq.1
The digit at the unit place is 2/3rd of the digit at the tens place
y = 2/3x
y = 2x/3.. Eq .2
Now substituting the value of y from Eq.. 2 to Eq..1
x + y = 10
x + 2x/3 = 10
(3x + 2x)/3 = 10
Cross multiplication
5x = 30
x = 30/5
x = 6
The 10s digit is 6
Substituting value of x in Eq..2 to drive value of y
y = 2x/3
y = 2 × 6/3
y = 2 × 2
y = 4
The 1s digit is 4
Thus the number is 64.
Explanation:
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