Q. 31. Draw an equilateral triangle whose each side is 4.5 cm
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Equilateral triangle
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Step-by-step explanation:
Step-1- Draw a line segment BC of length 4.5 cm
Step-2- From B, point A is at a distance of 5 cm. So, with B as center, draw an arc of radius 5 cm. (Now A will be somewhere on this arc. Our job is to find where exactly A is)
Step-3- From C, point A is at a distance of 4.5 cm. So, with C as center, draw an arc of radius 4.5 cm. (A will be somewhere on this arc, we have to fix it).
Step-4- A has to be on both the arcs drawn. So, it is the point of intersection of arcs. Mark the point of intersection of arcs as A. Join AB and AC. ∆ABC is now ready
Pls find the attachment of the drawn figure and steps bellow
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