Physics, asked by bibek99, 10 months ago

Q.32 AN ELLIPSOIDAL BODY IS
CARVED WITHIN A PERFECT
CONDUCTOR. A POSITIVE
CHARGE IS PLACED AT THE
CENTER OF CAVITY. THE
POINT A AND BARE ON THE
SURFACE OF CAVITY AS
SHOWN IN THE FIG. THEN​

Answers

Answered by Anonymous
0

Answer:

Explanation:

Electric field at A is different from field at B because, E=  

r  

2

 

K

​  

 

we know that conductor is equipotential  surface, so potential will be same at A and B.

As charge density ,σ∝  

r

1

​  

, then charge density is different at A and B.

Using Gauss's law, flux through the surface of the cavity, ϕ=  

ϵ  

0

​  

 

q  

enclosed

​  

 

​  

=  

ϵ  

0

​  

 

q

​  

 

Ans: (C),(D)

Answer By

Answered by RP7
1

Answer:

ans is c and d

mark me BRAINLIEST

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