Question

Q 33. The sum of AP: 1/15, 1/12,
1/10, .....to 11 terms.​

Answer 1

Step-by-step explanation:

Sum of n terms of AP formula:

Sn=2n[2a+(n−1)d] ......(1)

Where

First term =a

Common difference=d

Number of terms=n

1/15,1/12,1/10,..... to 11 terms

a=1/15

d=(1/12)−(1/15)=1/60

Using (1)

S11=11/2[2(1/15)+(11−1)(1/60)]

=(11/2)×[(2/15)+(1/6)]

=33/20

Sum of 11 terms of this AP is 33/20.