Q.34. Solve the equation z^2=z', where z is a complex
number. (z'=z bar).
Answers
Answered by
4
Answer:
The equation solution z^2 = zˉ ,where z is a complex number has 4 solutions.
Step-by-step explanation:
z2 = z ⇒ x2 – y2 + i2xy = x – iy
Therefore, x2 – y2 = x ...(1)
and 2xy = – y ... (2)
From (2), we have y = 0 or x = -1/2
When y = 0, from (1), we get
x2 – x = 0, i.e., x = 0 or x = 1.
When x =-1/2, from (1), we get
y2 = 1/4 +1/2 or y2 =3/4,
i.e., y =±√3/2
Answered by
3
Answer:
z^2 =z= x^2 -y square +12xy=x-y
We have y=0 or x=-1/2
when y =0, we get x^2-x=0 i.e x=0 or x=1
when x =-1/2,we get y square 1/4+1/2
solutions of given equation are
0+i0,1+i0 ,-1/2+i √3/2,-1/2-i √3/2
Step-by-step explanation:
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