Question

Q.35. Rationalize the denominator
1/root7-root6​

Answer 1

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Answer 2

Answer:

$\red{ \bold{answer: - }}$

$\frac{1}{ \sqrt{7} - \sqrt{6} } \\ \frac{1}{ \sqrt{7} - \sqrt{6} } \times \frac{ \sqrt{7} + \sqrt{6} }{\sqrt{7} + \sqrt{6} } \\ \frac{ \sqrt{7} + \sqrt{6} }{ \sqrt{7}^{2} - \sqrt{6}^{2}} \\ \frac{ \sqrt{7} + \sqrt{6} }{7 - 6} \\ \frac{ \sqrt{7} + \sqrt{6} }{1} \\ \sqrt{7} + \sqrt{6} \: \red{ \bold{ans.}}$

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