Question

Q 35 ?
Solution please

Answer 1

Answer:

ans of 35 is

tvcos Φ

bcoz in this case p have 2 comportment

1 is Tvsin Φ and

2 is Tvcos Φ we need

P and Q so our ans is

Tvcos Φ

Answer 2

Step-by-step explanation:

$t = \frac{2v \sin( \alpha ) }{g \cos( \ \beta ) }$

therefore ,

$range = \frac{2 {v}^{2} \sin( \alpha ) \cos( \alpha ) }{g \sin( \beta ) }$

substitute the value of t in range and you will get range as

$tv \cos( \alpha)$