Question

Q.36
3
Correct statement regarding this reaction
BF: + NH3-[F3B+ NH3]
(1) Hybridisation of N is changed
(2) Hybridisation of B is changed
(3) NH, act as a lewis base
(4) (2) and (3) both​

Answer 1

Explanation:

BF3 is a lewis acid whereas NH3 is a lewis base. NH3 donates its lone pair to BF3 and forms a dipolar bond. NH3 gets a positive formal charge and BH3 gets a formal negative charge

4.2

Answer 2

Answer:

The atomic number of boron is 5 & its electronic configuration in ground state  is 1s2 2s2 2p1, & in excited state is 1s2 2s1 2p2 , this means its one s & 2 p orbital will take part in hybridization to form sp2  hybrid orbital.

Similarly N atom has atomic number of 7, with electronic configuration of 1s2 2s2 2p3 in its ground state & in it excited state it has sp3 hybridization.

Now according to the question Boron & Nitrogen in reactant stage has sp2 & sp3  hybridization respectively, but on the product side an adduct is formed, wherein Boron has changed it s hybridization to sp3 while Nitrogen remains in same sp3 hybridization