Question

Q 36 A car moves with a speed of 40 km/h for 30 minutes and then with a speed of 60 km/h for the next 15 minutes. Calculate the total distance covered by the car.


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Answer 1

$\large\underline{\underline{\maltese{\red{\pmb{\sf{\:Given :-}}}}}}$

• ➬ A car moves with a speed of 40 km/h for 30 minutes .
• ➬ Than it moves with a speed of 60 km/h for 15 minutes .

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$\large\underline{\underline{\maltese{\red{\pmb{\sf{\: To \: Find:-}}}}}}$

• ➬ Total distance covered by car = ?

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$\large\underline{\underline{\maltese{\red{\pmb{\sf{\:Solution :-}}}}}}$

❒ Formula Used :

$\large\blue\bigstar{\underline{\boxed{\color{maroon}{\sf{Distance = Speed \times Time}}}}}$

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❒ Required Converting :

1 hr = 60 min.Hence ,

• ➳ First Case :

$\blue\leadsto{\sf{ T{\small_{1}} = \cancel\dfrac{30}{60}}}$

$\red{:\leadsto{\underline{\sf{ 0.5 \: hrs}}}}$

• ➳ 2nd Case :

$\blue\leadsto{\sf{ T{\small_{2}} = \cancel\dfrac{15}{60}}}$

$\red{:\leadsto{\underline{\sf{ 0.25 \: hrs}}}}$

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❒ Distance covered in both cases :

1st Case :

${:\longmapsto\sf{ Distance = Speed \times Time}}$

${:\longmapsto\sf{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 40 \times 0.5}}$

$\large\green{:\longmapsto{\underline{\sf{D{\small_{1}} = 20 km}}}}$

2nd Case :

${:\longmapsto\sf{ Distance = Speed \times Time}}$

${:\longmapsto\sf{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 60 \times 0.25}}$

$\large\green{:\longmapsto{\underline{\sf{D{\small_{2}} = 10 \: km}}}}$

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❒ Total Distance covered :

${:\longmapsto\sf{Total \: Distance = D{\small_{1}} + D{\small_{2}}}}$

${:\longmapsto\sf{ \: \: \: \: \: \: \: \: \: \: \: 20 \: km+ 10 \: km}}$

$\large\blue{:\longmapsto{\orange{\underline{\overline{\boxed{\sf{ 30 km}}}}}}}$

❒ Therefore :

❝ Total distance covered is 30 km . ❞

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