Question

Q 36 and 37 mentioned in the attachment

Answer 1

Answer:

0

Explanation:

Resultant = $\sqrt{A^{2} + B^{2} + 2ABcos}$θ

If θ = 0 Then

R = $\sqrt{A^{2} + B^{2} + 2ABcos(0)}$

Cos(0) = 1

R = $\sqrt{A^{2} + B^{2} + 2AB}$

As $(A + B)^{2}$ =$A^{2} + B^{2} + 2AB$

$\sqrt{A^{2} + B^{2} + 2AB}$ = A+B

Therefore,

R = A+B = B + A