Q 36(%x7+%*3)
A metal oxide P reacts with water and forms a metal hydroxide Q. On the other hand, a gas R is obtained
at a anode during the electrolysis of brine . Now, when R is passed over dry @ it gives compounds
which is used for disinfecting drinking water.
a) Identify P.Q.R.S. Write the chemical equations involved,
b) Name the process used in the formation of R and write two uses of R.
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Answers
Answer:
subject ................................
P is CaO
Q is Ca(OH)2
R is Cl2
S is Ca(OCl)2
Explanation:
We know that on electrolysis of Brine solution, at the anode, Chloride ion is oxidised to Chlorine gas (Cl₂)
Therefore, R is Cl₂
When R (Cl₂) is passed over dry Q then compound S is obtained which is used to disinfecting drinking water
Therefore, the compound S can be bleaching powder [Ca(OCl)₂]
In this case the the compound Q which is a metal hydroxide will be Ca(OH)₂
Therefore, the metal oxide P will be CaO
The equations will be
CaO + H₂O → Ca(OH)₂
NaCl → Na⁺ + Cl?⁻
Cl⁻ + Cl⁻ → Cl₂ + 2e?⁻
2Ca(OH)₂ + 2Cl₂ → Ca(OCl)₂ + CaCl₂ + 2H₂O
The process of obtaining Cl₂ is known as chloralkali process
The two uses of Cl₂ are as follows:
(i) Cl₂ is used as disinfectant both for drinking water and swimming pool water
(ii) Cl₂ is used as bleaching agent
Hope this answer is helpful.
Know More:
Q: A metal carbonate X on reacting with an acid gives a gas which when passed through a solution Y gives the carbonate back. On the other hand, a gas G that is obtained at anode during electrolysis of brine is passed on dry Y, it gives a compound Z, used for disinfecting drinking water. Identity X, Y, G and Z
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