Math, asked by renuagrawal62282, 5 days ago

Q.37 A person preparing a medicine wants to convert 15% alcohol solution into 32%
alcohol solution. Find how much pure alcohol he should mix in 40 mL of 15% alcohol
solution to obtain required solution?​

Answers

Answered by niravshah0111
1

Answer:

100ml

Step-by-step explanation:

Let the amount of pure alcohol he should mix in 400 ml of 15% alcohol be x

15% of 400 + x = 32% of (400 + x)

⇒ (15/100) × 400 + x = (32/100) × (400 + x)

⇒ 6000 + 100x  = 12800 + 32x

⇒ 6000 + 100x  = 12800 + 32x

⇒ x = 100ml

[The 40 ml in the question should be 400 otherwise, the answer would come in decimal which is not possible. It must be 400ml]

Hope it helps!!!!!! :)

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