Question

Q.37 In an electrical circuit two resistor
20 & 30 are connected in series with 10v
battery. The power dissipated across 30
resistor:
1000
[A] 3w
[B] 6w
[C] 12w
[D] 1-5w​

Answer 1

Answer:

(A) 3W

Explanation:

R1 = 20, R2 = 30, v = 10V

Power = V²/R

P = 10*10 / 30

P = 100/30

P = 3.33 W

So, the answer closest to your question is A.

I REALLY HOPE THIS HELPED YOU!