Q.37 Mention proper order of bond length given below
(i) N2 < N22- < N2
(ii) N22- < N2- < N2
(iii) N2" <N2 < N22-
(iv) N2 - < N22- < N2-
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Answer:
N
2
2−
=
2
10−6
=2
O
2
=
2
8−4
=2
NO
−
=
2
10−6
=2
Note:All the above molecules have bond order 2
No.of electrons in a) N
2
2−
= {7x2}+2=16 electrons
b) O
2
= (8x2)=16 electrons
c) NO
−
= 7+8+1=16 electrons
Hence all the three molecules are iso electronic too
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