Question

Q: 38 / 45
+4 -1
A stone is dropped from height h. At
2
position
it's velocity is 10 m/s, then what will be h-
(1) 8 m
(2) 10 m
(3) 12 m
(4) 16 m
A 1​

Answer 1

Answer:

u=0 m/s ( as it is said dropped and it means thrown with 0 initial velocity and without applying extra force)

v= 10 m/s

a= 10m/s^2

t=?

s =? (x)

by applying 3rd equation of motion

i.e 2as = v^2 - u^2

putting values

2(10)x = (10)^2 - (0)^2

20x = 100 - 0

20x = 100

x = 100/20

x = 5

so displacement is 5 meter

so height = 2× displacement

height = 10m

Explanation:

hope you understand

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